I was looking to overlay annotation on my phylogeny made,which was solved here question asked where i was looking to compare two different phylogeny which i could do.

Now i want to label the tips into various groups such as if its human or canine etc.One of the possible solution i found is this one not sure how to implement it.

alignment file annotation file


a<-read.alignment("clean_dup_align_fast.fas", format="fasta") 
pars.a <- optim.parsimony(upgma.a, a.phydat)
pars.a<-acctran(pars.a, a.phydat)
pars.a.rooted<-root(pars.a, outgroup="AAA64460", resolve.root=T)

i want to label according to the start column which is my source in my annotation file Any suggestion or help would be really appreciated

My working solution using this , this works as I did the alignment of sequences using full header name which kind of help to look for the pattern and grep it. The data file

I would still like to see the ggtree way instead of putting lots of label in the plot I would only like to see if I can annotate all the tips which have one organism source as one color rather putting all the labels

# "Phylogenetic tree with 516 tips and 514 internal nodes"

# by using the class() function
# "phylo"

# or by using the str() structure function
# "List of 4"
# this list includes $edge, $Nnode, $ tip.label and $edge.length
# the tree$tip.label includes family designation
#tree$tip.label  # 516 of these
# from the Science paper, we have seven kinase families:
# kinase categories... TK, TKL, STE, CK1, AGC, CAMK, CMGC
# with the following colours
# "red", "green", "paleblue", "orange", "yellow", "purple", "pink", "green" 

# by using the grep()function on the tree$tip.label part of the object
# we can find the tip labels that include "TK/" - i.e. tyrosine kinases
#grep("TK/", tree$tip.label)  # gives a list of numbers with "TK/" in tip label
#length(grep("TK/", tree$tip.label))

# thus there are 94 tip labels with that are designated TK (not TKL tyrosine kinase like)

# make a vector for each tip.label called tipcol with black on all of these...
#tipcol <- rep('black', length(tree$tip.label))
tipcol <- rep('black',length(pars.a$tip.label))

# make a vector with our list of kinase categories
#kinaseCats <- c("TK/", "TKL", "STE", "CK1", "AGC", "CAMK", "CMGC", "RGC")
kinaseCats <- c("Human","Rat","Murine","Bovine","Canine","Feline","Porcine","Gallus","Bat","Infectious","Transmissible")

# make a vector of color we want:
colorsList <-c("red", "darkolivegreen3", "blue", "orange", "blueviolet", "purple", "pink", "green","brown","navyblue","purple4")

# replace colours where grep gives "TK" as red, etc in a loop
#for(i in 1:length(kinaseCats)){
 # tipcol[grep(kinaseCats[i], tree$tip.label)] <- colorsList[i]

for(i in 1:length(kinaseCats)){
  tipcol[grep(kinaseCats[i], pars.a$tip.label)] <- colorsList[i]

# plot with edge length false to see nodes better
 #    use.edge.length = FALSE,
  #   tip.color=tipcol, 
   #  cex = 0.25)

     use.edge.length = FALSE,
     cex = 0.5)
# slow to draw due to text - a bit annoying!

figure plot


1 Answer 1


there are nice features in R ggtree package. You may use the geom_cladelabel() function for your purposes. But I haven't find yet a way to automatize clade annotation. To do it, you have to be sure of the clade homogeneity before removing tiplabs. here are some commands to do clade label annotation:

annot<-read.delim("annota.txt", header = T)

#find the node number corresponding to the common ancestor of the top clade in you tree
MRCA(ggtr, "AAL40400", "AAF25519")
#here, check that all accessions belong to the same organism/group
subset(annot, label=="AAL40400" | label=="AAF25519")
#in this case, sequences are related to bovine.
g<-g + geom_cladelabel(node=89, label="Bovine", align=F, fontsize=4)

#another example
MRCA(ggtr, "AAA46456", "AAF97738")
subset(annot, label=="AAA46456" | label=="AAF97738")
g<-g+ geom_cladelabel(node=73, label="Rodent", align=F, fontsize=4)

build with ggtree

  • $\begingroup$ looks bit more complicated due to this "have to be sure of the clade homogeneity" if there is a mix up then its difficult $\endgroup$
    – kcm
    May 28, 2020 at 8:28
  • 1
    $\begingroup$ you may keep tip labels where clade are heterogeneous. Or you should consider smaller clades or consider larger taxonomic groups (eg I summarized mice and rats as rodents in the second example). In any case, i think it deserve a visual/manual inspection to ensure the correctness. $\endgroup$ May 28, 2020 at 8:31
  • 1
    $\begingroup$ yes it is fully customizable. Finding the appropriate number is the more fastidious step I think. There is probably a way to automatize it however. $\endgroup$ May 28, 2020 at 8:44
  • 1
    $\begingroup$ nodelabels(cex=0.4) this is how i can label the node in base R which i was doing it is the same for the object which is made using this "g<-ggtree(ggtr)" $\endgroup$
    – kcm
    May 28, 2020 at 8:46
  • 1
    $\begingroup$ this a good thing to identify interesting node numbers! $\endgroup$ May 28, 2020 at 8:52

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