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Hi all, I encountered this question in a textbook (source: https://citeseerx.ist.psu.edu/viewdoc/download?doi=10.1.1.721.2540&rep=rep1&type=pdf) and was trying to workout the solution for it. Was wondering for the last question, wouldn't the probability be 0?

My working:

START -> M1 -> M2 -> M3 -> M4 -> M5 -> M6 -> M7 -> END

Probability Vector [A, T, C, G]

M1 : [0.6, 0.4, 0, 0]

M2 : [0.6, 0.4, 0, 0]

M3 : [0.4, 0.4, 0.2, 0]

M4 : [0.6, 0.4, 0, 0]

M5 : [0.4, 0.6, 0, 0]

M6 : [1, 0, 0, 0]

M7 : [0, 0, 0, 1]

To generate CTAAAAG = 0 * 0.4 * 0.4 * 0.6 * 0.4 * 1 * 1 = 0

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  • $\begingroup$ Hi @xxxcompbioxxx, if you need to adjust the original question, you can use the edit button there. $\endgroup$
    – Kamil S Jaron
    Sep 20 at 9:10