I trying to write a pythonic PyMol script that loads a PDB, cmd.iterates through the PDB and stores the residues (three letter code) into an array. I then want to loop through this array and calculate the center of masses (COM) of each aa's sidechains (except gly) and add it into a second array. I am able to calculate the COM of a residue as a whole, i.e. including backbone atoms. But what I want to calculate is the COM of the sidechain. Please point me in the right direction.

path = 'Path to PDB dir'
for filename in glob.glob(os.path.join(path, '*.PDB')):
    stored_residues = []
    cmd.iterate('name ca', 'stored_residues.append(resn)')

    stored_residues_COM = []

    for i in stored_residues:
         stored_residues_sidechain_COM.append(centerOfMass('resn %s' % i))

1 Answer 1


I am guessing you used the command pymol.cmd.centerofmass? If so the selector is the ticket to doing it by selecting everything of the residue bar the backbone atoms, e.g. f'resi {r} not name N+CA+C+O+H'

Parenthetically, the cmd.iterate command is really ugly and counter-intuitive —it's heavily used because it is older. The command get_model(selection) in pymol2 module is so much nicer.

for atom in pymol.cmd.get_model('name CA').atom:
     atom.resi #note it is type str due to insertion codes!
     atom.coords # List[float]

Second parenthesis. A and not element H is not needed or beneficial to pymol.cmd.centerofmass as this takes account of mass and occupancy. There is no need to select only heavy atoms as a proton weighs nothing. The barycentre and centroid are the same in geometry where there is no mass to the points, but here mass is present.

  • 1
    $\begingroup$ That is good advice. Thank you. I am also looking at Thomas Holder's code (pymolwiki.org/index.php/Sidechaincenters) as a comparative approach. $\endgroup$
    – gwot
    Commented Dec 9, 2021 at 14:09
  • 1
    $\begingroup$ @gwot Upvoting and checking 'answer resolved' is a good way to say thanks $\endgroup$
    – M__
    Commented Jan 7, 2022 at 14:59
  • $\begingroup$ Hi Matteo, sorry for the breach of etiquette. I have accepted you helpful answer, but do not yet have the rep to upvote. $\endgroup$
    – gwot
    Commented Jan 8, 2022 at 15:10

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